Solving the Common Core-aligned curriculum that equates mathematical concepts to stories called Eureka Math might be hard for some people. Fortunately, the answer key is everywhere on the internet. This post especially will inform you about the answer key of Lesson 17 Homework 4.3.
Show the division using disks. Relate your model to long division. Check your quotient and remainder by using multiplication and addition.
- 7 : 2
| Ones | |
| o o o o o o o | |
| o o o | |
| o o o |
Quotient: 3
Remainder: 1
Check your work:
3 x 2 = 6
6 + 1 = 7
- 73 : 2
| Tens | Ones |
| o o o o o
o o |
o o o
o o o o o o o o o o |
| o o o | o o o o o o |
| o o o | o o o o o o |
Quotient: 36
Remainder: 1
Check your work:
36 x 2 = 72
72 + 1 = 73
- 6 : 4
| Ones |
| o o o o o
o |
| o |
| o |
| o |
| o |
Quotient: 1
Remainder: 2
Check your work:
4 x 1 = 4
4 + 2 = 6
Aside from the homework, you might also want to check out the answer key of the Lesson 17 Exit Ticket, as follows:
Show the division using disks. Relate your model to long division. Check your quotient by using multiplication and addition.
- 5 : 4
| Ones |
| o o o o o |
| o |
| o |
| o |
| o |
Quotient= 1
Remainder: 1
Just like Lesson 16, the whole and partition the chart are modeled into 4 parts to represent the divisor.
Check your work:
4 x 1 = 4
4 + 1 = 5
- 53 : 4
| Tens | Ones |
| o o o o o | o o o
o o o o o o o o o o |
| o | o o o |
| o | o o o |
| o | o o o |
| o | o o o |
After distributing 4 tens, 1 ten remains. I change 1 ten for 10 ones.
Quotient: 13
Remainder: 1
Check your work:
13 x 4 = 52
52 + 1 = 53
After doing the Lesson 17 Homework 4.3, you might continue doing the Lesson 18 Homework 4.3. If you want to check how much do you get right, here is the answer key:
Solve using the standard algorithm. Check your quotient and remainder by using multiplication and addition.
- 84 : 2
- 84 : 4
- 48 : 3
- 80 : 5
- 79 : 5
- 91 : 4
- 91 : 6
- 91 : 7
- 87 : 3
- 87 : 6
- 94 : 8
- 94 : 6
In addition, you can also check out the answer key of the Lesson 19 Homework 4.3 below:
- When you divide 86 by 4 there is a remainder of 2. Model this problem with number disks. In the number disk model, how can you see that there is a remainder?
| Tens | Ones |
| o o o o o
o o o |
o o o o o
o |
| o o | o |
| o o | o |
| o o | o |
| o o | o |
I can see that 2 ones are still left over.
- Francine says that 86 : 4 is 20 with a remainder of 6. She reasons it is correct because (4 x 20) + 0 – 86. What mistake has Francine made? Explain how she correct her work.
Francine’s mistake is that her remainder is greater than her divisor. Instead of 20 groups, she can make one more group. 86 : 4 is 21 with a remainder of 2. (4 x 21) + 2 = 86.
- The number disk model is showing 67 : 4. Complete the model. Explain what happens to the 2 tens that are remaining in the tens column.
| Tens | Ones |
| 10 10 10 10 10
10 |
1 1 1 1 1
1 1 1 1 1 1 1 1 1 1 1 1 |
| 10 | 1 1 1 1 |
| 10 | 1 1 1 1 |
| 10 | 1 1 1 1 |
| 10 | 1 1 1 1 |
The 2 tens remaining get decomposed into 20 ones in the ones column.
- Two friends share 76 blueberries.
a. To count the blueberries, they have put them into small bowls of 10. Draw a picture to show how the blueberries can be shared equally. Will they have to split apart any of the bowls of 10 blueberries when they share them?
| 10 10 10 10 10
10 10 |
1 1 1 1 1
1 1 1 1 1 1 1 1 1 1 1 |
| 10 10 10 | 1 1 1 1 1 1 1 1 |
| 10 10 10 | 1 1 1 1 1 1 1 1 |
Yes, they will have to split apart one of the bowls.
b. Explain how the friends can share the blueberries fairly.
The friends will get 3 bowls and 8 single berries to give each friend 38 berries.
- Imagine you are drawing a comic strip showing how to solve the problem 72 : 4 to new fourth graders. Create a script to explain how you can keep dividing after getting a remainder of 3 tens in the first step.
| Tens | Ones |
| o o o o o
o o |
o o o o o o o o o o
o o o o o o o o o o o o o o o o o o o o o o |
| o | o o o o o o o o |
| o | o o o o o o o o |
| o | o o o o o o o o |
| o | o o o o o o o o |
Watch as I divide 72 : 4 using a place value chart. First, I divide the tens. Each of the 4 groups have 1 ten. There are 3 tens remaining. I can continue dividing by decomposing the 3 tens into 3 ones. Now I have 32 ones. I can distribute the ones evenly into the 4 groups. Each group will have 8 ones. Now we see that 72 : 4 is 1 ten and 8 ones.
